本书以通俗易懂的语言详尽地介绍了用Python语言编写的100个算法实例。这些实例大体上按照“问题描述→问题分析→算法设计→确定程序框架→程序编码实现→运行结果→问题拓展”的流程进行讲解,每个实例又根据实际需要有所取舍。这些实例兼顾了趣味性、实用性和可操作性,而且大多是围绕一些经典算法问题展开的。
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【One-Line Pitch】
A hands-on collection of 100 classic algorithm problems solved in Python, each walked through from problem statement to code and output—ideal for beginners who want to build confidence, sharpen logic, and learn by doing rather than by theory alone.
【Book Arc】
- **Opening (~0%–9%)**: Introduces core algorithm concepts through simple, classic problems—like the hit-and-run license plate puzzle and Newton's method for finding equation roots—teaching loop design, iteration, and the importance of correct termination conditions.
- **Early (~9%–28%)**: Expands into search and math modeling, covering binary search (with a clear low/high/mid pointer walkthrough) and real-world math problems like the book-lending permutation count and progressive tax calculation using lists of tuples.
- **Middle (~28%–47%)**: Dives into array-based simulations and number theory, including the candy-sharing circle problem, the magician's card trick (a clever circular-array puzzle), and integer properties like Armstrong numbers, amicable numbers, and modular arithmetic for high-power tails.
- **Late (~47%–53%)**: Continues with number patterns and classic theorems, such as generating Pythagorean triples via two distinct formulas, emphasizing coprime conditions and the elegance of mathematical shortcuts over brute force.
- **Ending (~53%–100%)**: The excerpts taper off here; the full book extends into fractions, primes, logic puzzles, games, arrays, recursion, theorems, graphics, and mixed problems, each following the same structured "problem→analysis→design→code→output→extension" flow.
【Key Takeaways】
- **Structured problem-solving framework** (Opening): Every example follows a consistent pipeline—problem description, analysis, algorithm design, framework, code, results, and extension—making it easy to replicate the method on new problems.
- **Loop design is the backbone** (Opening): The hit-and-run example shows how to use flag variables to break nested loops efficiently, a practical trick for reducing unnecessary iterations.
- **Iteration requires careful condition logic** (Opening): Newton's method highlights a common beginner trap—using `abs(x - x0) >= 1e-5` instead of `< 1e-5`—because the loop must continue while the error is still large, not when it's small.
- **Binary search is a divide-and-conquer classic** (Early): The low/high/mid pointer technique is explained step-by-step with a concrete array, and the code distinguishes success (via `break`) from failure (via a sentinel `k = -1`), reinforcing control-flow mastery.
- **Data structures simplify real-world math** (Early): The tax calculator uses a list of tuples to encode tax brackets and rates, then iterates to accumulate owed tax—a clean pattern for table-driven logic.
- **Array simulation models physical processes** (Middle): The candy-sharing problem uses a list to track each child's sweets, with a while loop checking uniformity and nested for loops for halving and passing—showing how to translate a real-world process into code.
- **Mathematical shortcuts beat brute force** (Middle): The high-power tail problem (13^13's last three digits) demonstrates that only the last three digits matter in multiplication, so `last = last * x % 1000` avoids overflow and is far more efficient.
- **Variable initialization placement is critical** (Middle): The amicable numbers example warns that resetting accumulators inside vs. outside a loop changes results—a subtle bug that teaches disciplined state management.
【Reading Tips】
- **Skim the "problem analysis" sections** if you're comfortable with math; the real value is in the "algorithm design" and "code" parts, where the loop and data-structure choices are explained.
- **Deep-read the binary search and Newton's method chapters** (Early): They're foundational for understanding pointers, iteration, and termination conditions—master these before moving on.
- **Watch for the "problem extension" sections**: They often introduce alternative methods (e.g., sequential search vs. binary search) or variations (e.g., different digit-splitting orders), which are great for testing your understanding.
- **Type out and run the code yourself**: The book emphasizes complete, tested programs; hands-on execution in PyCharm or any IDE will solidify the patterns far better than reading alone.
- **Pay attention to the "notes" and "common mistakes"**: The amicable numbers bug and the Newton's method condition are the kind of pitfalls that will trip you up in real projects—internalize them.
【Coverage Limits】
This guide synthesizes only the first ~53% of the book (chapters 1–3 and part of later chapters); the remaining content—fractions, primes, logic puzzles, games, recursion, theorems, graphics, and mixed problems—is not covered in the excerpts.
Excerpt 1
性较强的编程问题,以提高读者的编程动手能力。 本书配套资源 本书涉及的所有实例源代码文件及拓展程序文件需要读者自行下载。请在华章官网 www.hzbook.com 上搜索到本书,然后单击“资料下载”按钮,即可在本书页面上找到“配书资源”下载链接。 本书读者对象 ·Python编程初学者; ·Python编程爱好者...
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Excerpt 2
由于执行了break语句而跳出循环,在此情况下,变量k的值由-1变成了一个大于等于0的数,即指针mid所指元素的下标值。所以在最后用选择结构来判定k的值,从而确定整个查找过程是否成功。 补充知识点: (1)continue语句 continue语句的格式为: continue continue语句用于Python...
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Excerpt 3
sult(sweet, j) # 输出当前每个孩子手中的糖果数 上面的代码在while循环结构中又包含了两个for循环。 while循环的循环条件为“10个孩子手中的糖果数不相同”,第一个for循环用来将当前每个孩子手中的糖果分成一半,同时将分配结果保存在数组t中。在分配时注意区分奇偶数糖果分配方式的不同。第二个...
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Excerpt 4
示。 图3.11 运行结果 7.问题拓展 将原程序稍做改动,在最初定义的时候给变量b和n赋初值0。完整的代码如下: #!/usr/bin/python3 # -*- coding: utf-8 -*- # @author : liuhefei # @desc: 亲密数 if __name__=="__main__...
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Excerpt 5
nd=" ") n += 1 if n % 10 == 0: # 每行输出8个数 print() print() 4.4 最大公约数 1.问题描述 求任意两个正整数的最大公约数(Greatest Common Divisor,GCD)。 2.问题分析 如果有一个自然数a能被自然数b整除,则称a为b的倍数,b为a的...
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Excerpt 6
录余数m所存储的位置i,即小数点后的位置。quotient[i]=m/n把第i次相除得到的商存储到数组中下标为i的位置。因每次除完之后,得到的余数肯定比除数n小,所以在下一次进行相除之前余数应先乘以10再运算。代码如下: remainder[m] = i # m:得到的余数;remainder[m]:该余数对应的...
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Excerpt 7
类推,直到第一行中大于1898且与1898最接近的那个素数为止。 4.确定程序框架 程序的流程图如图5.5所示。 图5.5 程序流程图 5.完整的程序 根据上面的分析,编写程序如下: #!/usr/bin/python3 # -*- coding: utf-8 -*- # @author : liuhefei #...
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Excerpt 8
析 显然,该题是一个逻辑推断问题。张三、李四和王五三个人都可能说真话,也都可能说假话,那么如何来判断他们到底谁在说谎呢? 由问题描述可得到如下三个结论: ·由于“张三说李四在说谎”,因此,如果张三说的是真话,则李四就在说谎;反之,如果张三在说谎,则李四说的就是真话。 ·由于“李四说王五在说谎”,因此,如果李四说的...
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